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\Delta _{f}U^{o} of formation of CH_{4}(g) at a certain temperature is –393 kJ mol–1. The value of \Delta _{f}H^{\ominus } is
(i) zero
(ii)  <\Delta _{f}U^{o}
(iii) >\Delta _{f}U^{o}
(iv) equal to \Delta _{f}U^{o}

Answers (1)

The answer is option (ii) <\Delta _{f}U^{o}

Explanation: The reaction for the formation of CH_{4} is:

CH_{4}+2O_{2}\rightarrow CO_{2}+2H_{2}O

\Delta n_{g}=1-3=-2

\Delta H^{o}=\Delta U^{o}+\Delta n_{g}RT

\Delta n_{g}=-2

Hence, \Delta H^{o}<\Delta _{f}U^{o}

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