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Describe the change in hybridization (if any) of the A l  atom in the following reaction.

\mathrm{AlCl}_3+\mathrm{Cl}^{-} \rightarrow \mathrm{AlCl}_4^{-}

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Initially, the aluminum is in the ground state and the valence orbital can be shown as:

Then the electron gets excited so, the valence orbital can be shown as:

excited state

So, initially, aluminum \left(A l C_3\right){\text {was }} s p^2 hybridization and hence has a trigonal planar shape.

Then it reacts with chloride ions to form A l C_4^{-}. Where it has the empty 3 p_z orbital which gets involved and the hybridization changes from s p^2 \rightarrow s p^3.

Hence there is a shape change from trigonal planar to tetrahedral.

Posted by

Divya Prakash Singh

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