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10.Determine order and degree (if defined) of differential equation

        y'' + 2y' + \sin y = 0

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Given function is
y'' + 2y' + \sin y = 0
Now, it is clear from the above that, the highest order derivative present in differential equation is  y^{''}

Therefore, order of given differential equation  y'' + 2y' + \sin y = 0 is  2
Now, the given differential equation is  a polynomial equation in it's derivatives   y^{''} \ and \ y^{'} and power raised to y^{''}  is 1
Therefore, it's  degree is 1

Posted by

Gautam harsolia

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