Q: 6 Diagonal AC of a parallelogram ABCD bisects (see Fig.
). Show that ABCD is a rhombus.
Given: DAC=
BAC ................1
DAC=
BCA.................2 (Alternate angles)
BAC=
ACD .................3 (Alternate angles)
From equation 1,2 and 3, we get
ACD=
BCA...................4
From 2 and 4, we get
ACD=
DAC
In ADC,
ACD=
DAC (proved above )
AD=DC (In a triangle,sides opposite to equal angle are equal)
A parallelogram whose adjacent sides are equal , is a rhombus.
Thus, ABCD is a rhombus.