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  • Differentiate each of the functions w.r. to x in (sec x – 1) (sec x + 1)

Differentiate each of the functions w.r. to x in

(sec x - 1) (sec x + 1)

Answers (1)

    y= \left( \sec x-1 \right) \left( \sec x+1 \right) =\sec ^{2}x-1=\tan ^{2}x~ \\ \\

    Now applying the concept of chain rule


\frac{dy}{dx}=\frac{d \left( \tan ^{2}x \right) }{dx}=2\tan x\sec ^{2}x \\ \\

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