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  • Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation: N 2 (g) + H 2 (g) gives 2NH 3 (g) (i) Calculate the mass of ammonia produced if 2.00 x 10^3 g dinitrogen reacts with 1.00

1.24    Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation:
        N_2\ (g) + H_2\ (g) \rightarrow 2NH_3\ (g)

      (i) Calculate the mass of ammonia produced if 2.00 × 10 3 g dinitrogen reacts with 1.00 ×10 3 g of dihydrogen.

Answers (1)

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Given that if 2.00\times10^3g of dinitrogen reacts with 1.00\times10^3g of dihydrogen.

From the reaction we have:

1 mole of dinitrogen weighing 28g reacts with 3 moles of dihydrogen weighing 6g to give 2 moles of ammonia weighing 34g.

Therefore, 2.00\times10^3g of N_{2} will react with H_{2}  = \frac{6}{28}\times200g = 428.6g.

Thus, here N_{2} is the limiting reagent while H_{2} is in excess.

So, 28g of N_{2} produces 34g of NH_{3}.

Therefore, 2.00\times10^3g of N_{2} will produce = \frac{34}{28}\times 2000g = 2428.57g of NH_{3}.

Posted by

Divya Prakash Singh

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