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  • Draw a circle of radius 4 cm. Draw any two of its chords. Construct the perpendicular bisectors of these chords. Where do they meet?

Q8. Draw a circle of radius 4 cm. Draw any two of its chords. Construct the perpendicular bisectors of these chords. Where do they meet?

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The steps of construction are:

(i) Draw the circle with O and a radius of 4 cm.

(ii) Draw any two chords \bar{AB}  \bar{CD } in this circle.

(iii) Taking A and B as centres and radius more than half AB, draw two arcs which intersect each other at E and F.

(iv) Join EF. Thus EF is the perpendicular bisector of the chord \bar{CD }.

(v) Similarly draw GH the perpendicular bisector of chord \bar{CD }.

These two perpendicular bisectors meet at O, the centre of the circle.

Posted by

Divya Prakash Singh

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