Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • During the medical check-up of 35 students of a class, their weights were recorded as follows:

2. During the medical check-up of 35 students of a class, their weights were recorded as follows:
4.2
Draw a less than type ogive for the given data. Hence obtain the median weight from the graph and verify the result by using the formula.

Answers (1)

best_answer

Taking upper-class interval on the x-axis and their respective frequencies on the y-axis,

14.4 Ogive 2

N= 35 \implies \frac{N}{2} = 17.5

Marking a point on the curve whose ordinate is 17.5 gives an x-ordinate= 46.5.

Hence, the Median of the data is 46.5

Now,

Weight

(Class)

 Frequency

Cumulative

Frequency
>38 0 0
38-40 3 3
40-42 2 5
42-44 4 9
44-46 5 14
46-48 14 28
48-50 4 32
50-52 3 35

N= 35 \implies \frac{N}{2} = 17.5
\therefore Median class = 46-48; Lower limit, l = 46; 

Cumulative frequency of preceding class, c.f. = 14; f = 14; h = 2
Median = l + \left (\frac{\frac{n}{2}-c.f}{f} \right ).W
\\ = 46+ \left (\frac{17.5-14}{14} \right ).2 \\ \\ = 46+\frac{7}{14}

= 46.5

Thus, the median using formula is 46.5 which verifies the result.

Posted by

HARSH KANKARIA

View full answer

Similar Questions

Trending Articles/News

anam-khan

Board Exam Date 2025 Live: Bihar Class 10, 12 model papers out, time table soon; updates on CBSE, UP

Latest Question