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Q2 (1)   E and F are points on the sides PQ and PR respectively of a \triangle PQR. For each of the following
            cases, state whether EF || QR :
            PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm and FR = 2.4 cm

         

Answers (1)

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(i)          

Given : 

PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm and FR = 2.4 cm

\frac{PE}{EQ}=\frac{3.9}{3}=1.3\, cm                       and               \frac{PF}{FR}=\frac{3.6}{2.4}=1.5\, cm

 

We have  

                \frac{PE}{EQ} \neq \frac{PF}{FR}

Hence, EF is not parallel to QR.

 

 

 

 

 

Posted by

seema garhwal

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