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Q2 (2)   E and F are points on the sides PQ and PR
             respectively of a triangle PQR. For each of the following
             cases, state whether EF || QR :
             PE = 4 cm, QE = 4.5 cm, PF = 8 cm and RF = 9 cm

Answers (1)

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(ii)          

Given : 

             PE = 4 cm, QE = 4.5 cm, PF = 8 cm and RF = 9 cm

\frac{PE}{EQ}=\frac{4}{4.5}=\frac{8}{9}\, cm                       and               \frac{PF}{FR}=\frac{8}{9}\, cm

 

We have  

                \frac{PE}{EQ} = \frac{PF}{FR}

Hence, EF is parallel to QR.

 

Posted by

seema garhwal

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