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  • E and F are points on the sides PQ and PR respectively of a triangle PQR. For each of the following cases, state whether EF || QR : PQ equals 1.28 cm, PR equals 2.56 cm, PE equals 0.18 cm and PF equals 0.36 cm

Q2 (3)   E and F are points on the sides PQ and PR respectively of a triangle PQR. For each of the following cases,

            state whether EF || QR : PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm and PF = 0.36 cm

Answers (1)

best_answer

(iii)          

Given : 

PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm and PF = 0.36 cm

\frac{PE}{PQ}=\frac{0.18}{1.28}=\frac{9}{64}\, cm                       and               \frac{PF}{PR}=\frac{0.36}{2.56}=\frac{9}{64}\, cm

 

We have  

                \frac{PE}{EQ} = \frac{PF}{FR}

Hence, EF is parallel to QR.

 

Posted by

seema garhwal

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