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$E^{}\Theta$ values of some redox couples are given below. On the basis of these values choose the correct option.
$E^{}\Theta$ values: $Br_{2}/Br^{-}=+1.90; Ag^{+}/Ag(s)=+0.80$

$Cu^{2+}/Cu(s)=+0.34; I_{2}(s)/I^{-}=+0.54$

(i) Cu will reduce $Br^{-}$
(ii) Cu will reduce Ag
(iii) Cu will reduce $I^{-}$
(iv) Cu will reduce $Br_{2}$

Answers (1)

The answer is the option (iv) Cu will reduce Br₂

Explanation: Compared to Cu, Br₂ is a better reducing agent.

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infoexpert24

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