Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

1.    Evaluate :

  (iii) \cos 48^{o}-\sin 42^{o}

Answers (1)

best_answer

\cos 48^{o}-\sin 42^{o}
The above equation can be written as ;
\cos (90^o-42^{o})-\sin 42^{o}....................(i)
It is known that \cos (90^o-\theta) = \sin \theta
Therefore, equation (i) becomes,
\sin42^{o}-\sin 42^{o} = 0

So, the answer is 0.

Posted by

manish

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE Board Exam 2025: Class 10, 12 practical exam dates out at cbse.gov.in; passing marks
anam-khan

CBSE urges schools to complete 100% registration of Class 9, 11 students by October 16; late fee for delays

Latest Question