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Q1. Evaluate.

    (ii)     (-4)^{-2}

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The detailed explanation for the above-written question is as follows

We know that,

a^{-m}= \frac{1}{a^{m}}

So, here (a = -4) and (m = 2)

Then according to the law of exponent 

(-4)^{-2}= \frac{1}{(-4)^{2}} = \frac{1}{(-4)}\times \frac{1}{(-4)} = \frac{1}{16}  [  negative \timesnegative = positive]

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manish

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