Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Evaluate the following 5 cos ^2 60 ^o + 4 sec ^2 30 ^o - tan ^2 45 ^o sin ^2 30 ^o + cos ^2 30 ^o

1.        Evaluate the following :

        (v)\frac{5\cos^{2}60^{o}+ 4\sec^{2}30^{o}-\tan^{2}45^{o}}{\sin^{2}30^{o}+\cos^{2}30^{o}}

Answers (1)

best_answer

\frac{5\cos^{2}60^{o}+ 4\sec^{2}30^{o}-\tan^{2}45^{o}}{\sin^{2}30^{o}+\cos^{2}30^{o}}.....................(i)
We know the values of-
\\\cos 60^0 = 1/2= \sin 30^0\\ \sec 30^0 = 2/\sqrt{3}\\ \tan 45^0 = 1\\ \cos 30^0 = \sqrt{3}/2
By substituting all these values in equation(i), we get;

\\\Rightarrow \frac{5.(\frac{1}{2})^2+4.(\frac{2}{\sqrt{3}}) ^2-1}{(\frac{1}{2})^2+(\frac{\sqrt{3}}{2})^2}\\ \Rightarrow \frac{5/4-1+16/3}{1}\\ \Rightarrow \frac{1/4+16/3}{1}\\ \Rightarrow\frac{67}{12}

Posted by

manish

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE 10th Second Board Result 2026 LIVE: Class 10 scorecard soon at cbse.gov.in; DigiLocker, UMANG app login
anam-khan

CBSE 2026 10th Second Board Result Date LIVE: Class 10 scores soon for over 6.68 lakh students; how to check
anam-khan

CBSE Class 10 Second Board Result 2026 LIVE: 10th scorecard for over 6.68 lakh soon; passing marks

Latest Question