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  • Explain on the basis of valence bond theory that [Ni(CN)_{4}]^{2-}ion with square planar structure is diamagnetic and the [NiCl_{4}]^{2-}ion with tetrahedral geometry is paramagnetic.

9.5    Explain on the basis of valence bond theory that   [Ni(CN)_{4}]^{2-}ion with square planar structure is diamagnetic and the [NiCl_{4}]^{2-}ion with tetrahedral geometry is paramagnetic.

 

 

 

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In both the compounds, the oxidation state of Nickel is +2. So it has d8 configuration. 

Now, on the basis of ligand pairing of electrons will occur. Since CN- is a strong ligand so pairing will occur but in case of  Cl- pairing will not be there as it is a weak ligand. So, the configuration of both the compounds looks like :- 

                                      

                                             

                                            

Thus  [Ni(CN)_{4}]^{2-} is a square planer and diamagnetic and  [NiCl_{4}]^{2-}  has tetrahedral geometry and is paramagnetic.

Posted by

Devendra Khairwa

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