Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Express sin 67^o plus cos 75^o in terms of trigonometric ratios of angles between 0^0 and 45^0.

7.  Express sin 67^{o}+\cos 75^{o}in terms of trigonometric ratios of angles between 0^{o} and 45^{o}.

Answers (1)

best_answer

By using the identity of \sin\theta and \cos\theta
sin 67^{o}+\cos 75^{o}
We know that, 
\sin(90-\theta) =\cos \theta and \cos(90-\theta) =\sin \theta
the above equation can be written as;
=\sin (90^0-23^0)+\cos(90^0-15^0)
=\sin (15^0)+\cos(23^0)

Posted by

manish

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE Board Exam 2025: Class 10, 12 practical exam dates out at cbse.gov.in; passing marks
anam-khan

CBSE urges schools to complete 100% registration of Class 9, 11 students by October 16; late fee for delays

Latest Question