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Q3 Factorise  

(II)

15 xy -6 x +5 y -2

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We have,
    15xy = 3 \times 5 \times x \times y
   6x = 2 \times 3 \times x
    5y = 5 \times y
    2 = 2
Therefore, on factorization we get,
 15xy - 6x +5y-2 = (3\times 5 \times x \times y)-(2 \times 3 \times x)+(5\times y)-2
                                            =(5 \times y)(3\times x + 1)-2(3\times x + 1)
                                            =(5y-2)(3x+1)
                

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Gautam harsolia

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