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Q2 Factorise 

(IV) 

16 x^5 - 144 x ^ 3

Answers (1)

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The given question can be factorised as follows
             16 x^5 - 144 x ^ 3 = 16x^3(x^{2}- 9)
                                           = 16x^3((x)^{2}- (3)^{2})= 16x^3(x-3)(x+3)                 (using \ (a)^{2}- (b)^{2} = (a-b)(a+b))

Posted by

Gautam harsolia

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