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Q2 Factorise

(VI)

$9 x ^2 y^2 - 16$

Answers (1)

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We have,
$9 x ^2 y^2 - 16$ = $(3xy)^{2} -(4)^{2}$ (using $(a)^{2} -(b)^{2} = (a-b) (a+b)$ )
$= (3xy - 4 )(3xy + 4)$

Posted by

Gautam harsolia

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