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q4) Factorise 

ii)

p ^ 4 - 81

Answers (1)

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We have,
              p ^ 4 - 81 =
                                        (p^{2})^{2} - (9)^{2} = (p^{2} - 9)(p^{2}+9) \\ . \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = (p^{2}-(3)^{2})(p^{2}+9)\\ .\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = (p-3)(p+3)(p^{2}+9)             using \ a^{2} - b^{2} = (a-b)(a+b)

Posted by

Gautam harsolia

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