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  • Fig. depicts an archery target marked with its five scoring regions from the centre outwards as Gold, Red, Blue, Black and White. The diameter of the region representing Gold score is 21 cm and each of the other bands is 10.5 cm wide. Find the area o

3.  Fig. depicts an archery target marked with its five scoring regions from the centre outwards as Gold, Red, Blue, Black and White. The diameter of the region representing Gold score is 21 cm and each of the other bands is 10.5 cm wide. Find the area of each of the five scoring regions.

                                                        

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Radius of each scoring region can be found by adding 10.5 in respective colours.

The area of golden region is :      =\ \pi r^2\ =\ \pi \times 10.5^2\ =\ 346.5\ cm^2

Similarly area of the red region is   =   Area of red and golden score  -  Area of golden region 

                                                     \\=\ \pi \times 21^2\ -\ \pi \times 10.5^2\\\\=\ 1039.5\ cm^2

Then area of blue region is : 

                                                    \\=\ \pi \times (31.5)^2\ -\ \pi \times 21^2\\\\=\ 1732.5\ cm^2

And area of the black region is :

                                                    \\=\ \pi \times 42^2\ -\ \pi \times (31.5)^2\\\\=\ 2425.5\ cm^2

Area of the white region is : 

                                                   \\=\ \pi \times 52.5^2\ -\ \pi\times 42^2\\\\=\ 3118.5\ cm^2

 

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Devendra Khairwa

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