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Q5.24. Figure 5.17 shows the position-time graph of a body of mass 0.04 kg. Suggest a suitable physical context for this motion. What is the time between two consecutive impulses received by the body? What is the magnitude of each impulse?

            

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From the graph, it is clear that the direction of motion is changing after every 2 seconds. And has the same magnitude after 2 seconds.

This can be understood from a situation that a ball collides with wall elastically in seconds and returns to the original mean position after 4 seconds.

Since the slope of the graph is changing after every 2 s, so impulse is given after 2 sec. of duration.

Velocity can be known by calculating the slope of the position-time curve.

                                            u\ =\ \frac{(2-0)}{2-0}\times 10^{-2}\ =\ 10^{-2}\ m/s

or                                             v\ =\ -\ 10^{-2}\ m/s

Therefore, the magnitude of impulse is given by   =      |  Change in momentum  | 

                                                                        I\ =\ |mv\ -\ mu|

or                                                                           =\ 0.04(-\ 10^{-2}\ -\ 10^{-2})

or                                                                           =\ 0.08\ \times 10^{-2}\ Kg\ m/s

Posted by

Devendra Khairwa

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