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3. Fill in the blanks:
                (a) 369 ÷ ___ = 369            (b) (–75) ÷ _ = –1
                (c) (–206) ÷ _ = 1 (d) – 87 ÷ _ = 87
                (e) _ ÷ 1 = – 87                (f) _ ÷ 48 = –1
                (g) 20 ÷ _ = –2                 (h) ___ ÷ (4) = –3

Answers (1)

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(a) Given, $369 \div \underline{\ \ \ \ \ \ } = 369$

A number divided by 1 gives the number itself.

$369 \div \underline{1} = 369$

(b) $(-75) \div \underline{\ \ \ \ \ } = -1$

The product is negative, therefore there must be odd number of negative integers.

$(-75) \div \underline{75} = -1$

(c) $(-206) \div \underline{\ \ \ \ }= 1$

A number divided by itself gives 1

$(-206) \div \underline{(-206)}= 1$

(d) $(-87) \div \underline{\ \ \ \ }= 87$

The product is positive, therefore there must be even number of negative integers.

$(-87) \div \underline{(-1) }= 87$

(e) $\underline{\ \ \ \ } \div 1 = - 87$

A number divided by 1 gives the number itself.

$\underline{(-87)} \div 1 = - 87$

(f) $\underline{\ \ \ \ \ } \div 48 = -1$

The product is negative, therefore there must be odd number of negative integers.

$\underline{(-48)} \div 48 = -1$

(g) $20\div \underline{\ \ \ \ \ } = -2$

The product is negative, therefore there must be odd number of negative integers.

$20\div \underline{(-10)} = -2$

(h) $\underline{\ \ \ \ \ } \div (4) = -3$

The product is negative, therefore there must be odd number of negative integers.

$\underline{\left (\frac{-4}{3} \right ) } \div (4) = -3$

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HARSH KANKARIA

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