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fill in blanks the set of value of \sec^{-1}\left (\frac{1}{2} \right ) is______________. 

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Fill in the blanks the set of value of \sec^{-1}\left ( \frac{1}{2} \right ) is \phi

Domain of sec-1 x is R – (-1,1).

As, -\frac{1}{2} is outside domain of sec-1 x.

Which means there is no set of value of \sec^{-1}\frac{1}{2}

So, the solution set of \sec^{-1}\frac{1}{2}  is null set or \phi

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