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  • Find an anti derivative (or integral) of the following functions by the method of inspection. cos 3x

 Q2  Find an anti derivative (or integral) of the following functions by the method of inspection. \cos 3x

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GIven \cos 3x;

So, the antiderivative of \cos 3x is a function of x whose derivative is \cos 3x.

\frac{d}{dx}\left ( \sin 3x \right ) = 3\cos3x

\implies \cos 3x =\frac{1}{3} \frac{d}{dx}\left ( \sin 3x \right )

Therefore, we have the anti derivative of \cos 3x is  \frac{1}{3}\sin 3x.

 

Posted by

Divya Prakash Singh

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