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  • Find an anti derivative (or integral) of the following functions by the method of inspection. sin 2x

Q1 Find an anti derivative (or integral) of the following functions by the method of inspection. \sin 2x

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GIven \sin 2x;

So, the anti derivative of \sin 2x is a function of x whose derivative is \sin 2x.

\frac{d}{dx}\left ( \cos 2x \right ) = -2\sin 2x

\implies \sin 2x =\frac{-1}{2} \frac{d}{dx}\left ( \cos 2x \right )

Therefore, we have \implies \sin 2x = \frac{d}{dx}\left ( \frac{-1}{2}\cos 2x \right )

Or, antiderivative of \sin 2x is \left ( \frac{-1}{2}\cos 2x \right ).

 

Posted by

Divya Prakash Singh

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