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2.6    Find energy of each of the photons which
  (i) correspond to light of frequency 3\times 10^{15}\ \textup{Hz}.

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If a photon has a frequency of \vartheta = 3\times10^{15} Hz.

Then, the energy of each of the photons will be:

E = h\vartheta = (6.626\times10^{-34}J.s)\times(3\times10^{15}s^{-1})

                 = 1.988\times10^{-18}J

 

Posted by

Divya Prakash Singh

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