Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find equation of the line parallel to the line 3x-4y+2=0 and passing through the point (-2, 3).

Q : 7      Find equation of the line parallel to the line  3x-4y+2=0  and passing through  the point (-2,3). 

Answers (1)

best_answer

It is given that line is parallel to line  3x-4y+2=0 which implies that the slopes of both the lines are equal
we can rewrite it as
y = \frac{3x}{4}+\frac{1}{2}
The slope of line 3x-4y+2=0  =  \frac{3}{4}
Now, the equation of the line passing through the point (-2,3) and with slope \frac{3}{4} is
(y-3)=\frac{3}{4}(x-(-2))
4(y-3)=3(x+2)
4y-12=3x+6
3x-4y+18= 0
Therefore, the equation of the line is  3x-4y+18= 0

Posted by

Gautam harsolia

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Date Sheet 2025 (Out) Live: Class 10, 12 board exam time table at cbse.gov.in; syllabus, sample papers
anam-khan

CBSE Class 12 board exam date sheet 2025 out; exams from February 15 to April 4
anam-khan

When will CBSE Board exam 2025 date sheet be released for Class 10, 12?

Latest Question