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1. Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60°.

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We know that the area of a sector having radius r and angle \Theta is given by:-  

                                                  Area\ =\ \frac{\Theta}{360^{\circ}}\times \pi r^2

Thus the area of the given sector is:- 

                                                               \\=\ \frac{60^{\circ}}{360^{\circ}}\times \pi \times 6^2\\\\=\ \frac{132}{7}\ cm^2

                                                      

Posted by

Devendra Khairwa

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