Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the area of the region bounded by the curves y = x^2 + 2, y = x, x = 0 and x = 3.

Q : 3 Find the area of the region bounded by the curves  \small y=x^2+2,y=x,x=0 and \small x=3. 

Answers (1)

best_answer

The area of the region bounded by the curves,

 \small y=x^2+2,y=x,x=0 and \small x=3 is represented by the shaded area OCBAO as

Then, Area OCBAO will be = Area of ODBAO - Area of ODCO

which is equal to 

\int_0^3(x^2+2)dx - \int_0^3x dx

= \left ( \frac{x^3}{3}+2x \right )_0^3 -\left ( \frac{x^3}{2} \right )_0^3

= \left [ 9+6 \right ] - \left [ \frac{9}{2} \right ] = 15-\frac{9}{2} = \frac{21}{2}units.


 

 

Posted by

Divya Prakash Singh

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Board Exams 2026: Online portal for availing CWSN facilities opens from September 9
anam-khan

CBSE announces deadline for Class 10, 12 direct admissions, subject change
anam-khan

CBSE warns about unauthorised sources offering ‘quick’ ways of getting duplicate marksheets, certificates

Latest Question