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  • Find the area of the triangle whose vertices are : (i) (2, 3), (–1, 0), (2, – 4)

1.(i)   Find the area of the triangle whose vertices are : (2, 3), (–1, 0), (2, – 4)

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As we know, the area of a triangle with vertices (x1,x2) ,(y1, y2) and (z1 z2 ) is given by :

A= \frac{1}{2}(x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2))

So Area of a triangle  whose vertices are(2, 3), (–1, 0)and (2, – 4) is

A= \frac{1}{2}[2(0-(-4))+(-1)(-4-3)+2(3-0)]

A= \frac{1}{2}[8+7+6]

A= \frac{1}{2}[21]

A= \frac{21}{2}

A= 10.5\:unit^2

Hence, The area of the triangle is 10.5 per unit square.

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Pankaj Sanodiya

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