Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the area of the triangle whose vertices are (–5, –1), (3, –5), (5, 2)

1.(ii)   Find the area of the triangle whose vertices are  (–5, –1), (3, –5), (5, 2)

Answers (1)

best_answer

From the figure:

triangle area 2

Area of the triangle is given by:

Area = \frac{1}{2}\left [ x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2}) \right ]

Substituting the values in the above equation, we obtain

Area = \frac{1}{2}\left [ (-5)((-5)-(-2))+3(2-(1))+5(-1-(-5)) \right ]

= \frac{1}{2}\left [ 35+9+20 \right ] = 32 \ square\ units.

Posted by

Divya Prakash Singh

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 10 board exams 2026 from February 17, May 15; tentative date sheet out for both phases
anam-khan

CBSE launches Integrated Payment System for Class 10, 12 payments; holds principals liable for errors
anam-khan

NEP 2020 gives Indian schools space for new way of learning, with creativity, contemplation

Latest Question