Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the centre and radius of the circles. x 2 + y ^ 2 - 8x + 10y - 12 = 0

8.  Find the centre and radius of the circles.

      x^2 + y^2 -8x +10y -12 = 0

Answers (1)

best_answer

As we know, 

The equation of the circle with centre ( h, k) and radius r is given by ;

(x-h)^2+(y-k)^2=r^2

Given here 

x^2 + y^2 -8x +10y -12 = 0

Can also be written in the form 

(x-4)^2 + (y-(-5))^2 = (\sqrt{53})^2

So, from comparing, we can see that 

r=\sqrt{53}

Hence the radius of the circle is \sqrt{53}.

Posted by

Pankaj Sanodiya

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Date Sheet 2025 (Out) Live: Class 10, 12 board exam time table at cbse.gov.in; syllabus, sample papers
anam-khan

CBSE Class 12 board exam date sheet 2025 out; exams from February 15 to April 4
anam-khan

When will CBSE Board exam 2025 date sheet be released for Class 10, 12?

Latest Question