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Find the coefficient of x in the expansion of \left ( 1-3x+7x^{2} \right )\left ( 1-x \right )^{16}

Answers (1)

(1-3x+7x2) (1-x)16        ….. (given)

= (1-3x+7x2) (106C0 - 16C1x1 + 16C2x2 + …… + 16C16x16)

= (1-3x +7x2) (1-16x+120x2+…..)

Thus, coefficient of x = -19
 

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