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  • Find the coordinates of a point A, where AB is the diameter of a circle whose centre is (2, – 3) and B is (1, 4).

7.   Find the coordinates of a point A, where AB is the diameter of a circle whose centre is (2, – 3) and B is (1, 4).

Answers (1)

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As the centre point C(2,-3) will be the mid-point of the diameter AB.

Then, the coordinates of point A will be A(x,y).

Given point B(1,4).

Therefore,

(2,-3) = \left ( \frac{x+1}{2}, \frac{y+4}{2} \right )

\frac{x+1}{2} = 2\ and\ \frac{y+4}{2} = -3

\Rightarrow x = 3\ and\ y = -10.

Therefore, the coordinates of A are (3,-10).

Posted by

Divya Prakash Singh

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