Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum. x ^2 = 6y

2. Find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum.

       x^2 = 6y

Answers (1)

best_answer

Given, a parabola with equation 

x^2 =6y

This is parabola of the form x^2=4ay which opens upward.

So,

By comparing the given parabola equation with the standard equation, we get,

4a=6

a=\frac{3}{2}

Hence,

Coordinates of the focus :

(0,a)=\left (0,\frac{3}{2}\right)

Axis of the parabola:

It can be seen that the axis of this parabola is Y-Axis.

The equation of the directrix

y=-a,\Rightarrow y=-\frac{3}{2}\Rightarrow y+\frac{3}{2}=0

The length of the latus rectum:

4a=4(\frac{3}{2})=6.

Posted by

Pankaj Sanodiya

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14
anam-khan

CBSE Board Exams 2025: Online portal for availing exemptions by CWSN students opens
anam-khan

Board Exams: States agree to equivalence; no question paper ‘jumbling’ from next year, says PARAKH CEO

Latest Question