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9.   Find the coordinates of the points which divide the line segment joining A (– 2, 2) and B(2, 8) into four equal parts.

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From the figure:

lin eratio

Points C, D, and E divide the line segment AB into four equal parts.

Now, from the section formula, we can find the coordinates of Point C, D, and E.

Section Formula:

 P(x,y)= \left (\frac{m_{1}x_{2}+m_{2}x_{1}}{m_{1}+m_{2}} , \frac{m_{1}y_{2}+m_{2}y_{1}}{m_{1}+m_{2}} \right )

Here point D divides the line segment AB into two equal parts hence 

D(x_{2},y_{2})= \left (\frac{-2+2}{2} , \frac{2+8}{2} \right )

D(x_{2},y_{2})= \left (0 , 5 \right )

Now, point C divides the line segment AD into two equal parts hence

C(x_{1},y_{1})= \left (\frac{-2+0}{2} , \frac{2+5}{2} \right )

C(x_{2},y_{2})= \left (-1 , \frac{7}{2} \right )

Also, point E divides the line segment DB into two equal parts hence

E(x_{1},y_{1})= \left (\frac{2+0}{2} , \frac{8+5}{2} \right )

E(x_{2},y_{2})= \left (1 , \frac{13}{2} \right )

Posted by

Divya Prakash Singh

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