Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the equation of a circle of radius 5 which is touching another circlex2 + y2 – 2x – 4y – 20 = 0 at (5, 5).

Find the equation of a circle of radius 5 which is touching another circle x2 + y2 – 2x – 4y – 20 = 0 at (5, 5).

Answers (1)

Given circle is x2+y2-2x-4y=20

(x-1)2+(y-2)2=52 

 Centre of this circle is C1(1,2).  

 Now, the required circle of radius'5'touches the above circle at P(5,5).  

  Let the centre of the required circle be C2(h,k). 

  Since the radius of the given circle and the required circle is same, point P is mid point of C1C2.

5=\frac{1+h}{2} and 5=\frac{2+k}{2}

h=9 and k=8

So the equation of the required circle is (x-9)2+(y-8)2=25

x2+y2-18x-16y+120=0

Posted by

infoexpert22

View full answer

Similar Questions

Latest Question