Find the equation of a curve passing through the point (1, 1). If the tangent drawn at any point P(x,y) on the curve meets the co-ordinate axes at A and B such that P is the mid-point of AB.
Points on the y axis and x axis are namely A(0,a), B(b,0). The midpoint of AB is P(x,y).
The x coordinate of the points is given by the addition of the x coordinates of A and B divided by 2.
Therefore, the coordinates of A and B are (0,2y) and (2x,0) respectively.
AB is the tangent to the curve where P is the point of contact.
The slope of the line given with two points
Here respectively.
The slope of the tangent AB is
Hence the slope of the tangent is -y/x
The slope of the tangent curve is given by,
Integrate
using logat logb=logab.
as given curve is passing through(1,a)
Hence (1,1) will satisfy the equation of the curve(a)
Putting
put c back in (a)
Hence the equation of the curve is