Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the equation of the line passing through the point (5, 2) and perpendicular to the line joining the points (2, 3) and (3, – 1).

Find the equation of the line passing through the point (5, 2) and perpendicular to the line joining the points (2, 3) and (3, – 1).

Answers (1)

 Given points are A(5,2) B(2,3) and C(3,-1).

  Slopeof the line joining points B and C = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{-1-3}{3-2}=-\frac{4}{1}=-4

It is given that line passing through the point A is perpendicular to BC 

   m1*m2= -1 

-4*m2=-1  

m2=1/4 

 Equation of line passing through point A  

  Equation of line: y-y1 = m(x-x1)   

 y-2=1/4 (x-5)  

 4y-8=x-5  

 x-5-4y+8=0   

  Equation of straight line passing through point A is x-4y+3=0  

Posted by

infoexpert22

View full answer

Similar Questions

Latest Question