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Find the equation of the line which satisfy the given conditions: 

Q : 5         Intersecting the x-axis at a distance of 3 units to the left of origin with slope -2

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We know that the equation of the line passing through the point (x_1,y_1) and with slope m is given by
(y-y_1)=m(x-x_1)
Line Intersecting the x-axis at a distance of 3 units to the left of origin which means the point is (-3,0)
Now, the equation of the line passing through the point (-3,0) and with slope -2  is 
(y-0)= -2(x-(-3))\\ y = -2x-6\\ 2x+y+6=0
Therefore, the equation of the line  is   2x+y+6=0

Posted by

Gautam harsolia

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