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Find the equation of the line which satisfy the given conditions: 

Q : 2         Passing through the point  (-4,3)  with slope  \frac{1}{2}.

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We know that , equation of line passing through point (x_1,y_1) and with slope m is given by
(y-y_1)=m(x-x_1)
Now,  equation of line passing through point (-4,3) and with slope \frac{1}{2} is 
(y-3)=\frac{1}{2}(x-(-4))\\ 2y-6=x+4\\ x-2y+10 = 0
Therefore, equation of the line  is   x-2y+10 = 0

Posted by

Gautam harsolia

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