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Find the equation of the line which satisfy the given conditions: 

Q : 7         Passing through the points  (-1,1)  and (2,-4).

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We know that , equation of line passing through point (x_1,y_1) and with slope m is given by
(y-y_1)=m(x-x_1)
Now, it is given that line passes throught point (-1 ,1) and (2 , -4)
m = \frac{y_2-y_1}{x_2-x_1}\\ \\ m = \frac{-4-1}{2+1}= \frac{-5}{3}
Now,  equation of line passing through point (-1,1) and with slope \frac{-5}{3}  is 
(y-1)= \frac{-5}{3}(x-(-1))\\ \\3(y-1)=-5(x+1)\\ 3y-3=-5x-5\\ 5x+3y+2=0
 

Posted by

Gautam harsolia

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