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8.  Find the indicated terms in each of the sequences in Exercises 7 to 10 whose nth terms are: 

     a _n = \frac{n^2 }{2^n } ; a_7

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Given :  a _n = \frac{n^2 }{2^n }

 Put n=7,

a _7 = \frac{7^2 }{2^7 } =\frac{49}{128}

Heence, we have a _7 =\frac{49}{128}

Posted by

seema garhwal

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