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2. Find the mean deviation about the mean for the data.

   \small 38,70,48,40,42,55,63,46,54,44

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Mean (\overline{x}) of the given data:

\\ \overline{x} = \frac{1}{8}\sum_{i=1}^{8}x_i = \frac{38+70+48+40+42+55+63+46+54+44}{10} \\ = \frac{500}{10} = 50

The respective absolute values of the deviations from mean, |x_i - \overline{x}| are

12, 20, 2, 10, 8, 5, 13, 4, 4, 6

\therefore  \sum_{i=1}^{8}|x_i - 50| = 84

\therefore M.D.(\overline{x}) = \frac{1}{n}\sum_{i=1}^{n}|x_i - \overline{x}|

= \frac{84}{10} = 8.4

Hence, the mean deviation about the mean is 8.4.

Posted by

HARSH KANKARIA

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