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3. Find the mean deviation about the median.

   \small 13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17

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Number of observations, n = 12, which is even.

Arranging the values in ascending order:

10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18.

Now, Median (M)

\\ = \frac{(\frac{12}{2})^{th} observation + (\frac{12}{2}+ 1)^{th} observation}{2} \\ = \frac{13 + 14}{2} = \frac{27}{2}= 13.5

The respective absolute values of the deviations from median, |x_i - M| are

3.5, 2.5, 2.5, 1.5, 0.5, 0.5, 0.5, 2.5, 2.5, 3.5, 3.5, 4.5

\therefore  \sum_{i=1}^{8}|x_i - 13.5| = 28

\therefore M.D.(M) = \frac{1}{12}\sum_{i=1}^{n}|x_i - M|

= \frac{28}{12} = 2.33

Hence, the mean deviation about the median is 2.33.

Posted by

HARSH KANKARIA

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