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Find the multiplicative inverse of each of the complex numbers.

Q : 11    4-3i

Answers (1)

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Let    z = 4-3i
Then,
\bar z = 4+ 3i
And 
|z|^2 = 4^2+(-3)^2 = 16+9 =25
Now, the multiplicative inverse is given by
z^{-1}= \frac{\bar z}{|z|^2}= \frac{4+3i}{25}= \frac{4}{25}+i\frac{3}{25}

Therefore, the multiplicative inverse is

   \frac{4}{25}+i\frac{3}{25}

Posted by

Gautam harsolia

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