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Find the multiplicative inverse of each of the complex numbers.

Q : 13        -i

Answers (1)

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Let    z = -i
Then,
\bar z = i
And 
|z|^2 = (0)^2+(1)^2 = 0+1 =1
Now, the multiplicative inverse is given by
z^{-1}= \frac{\bar z}{|z|^2}= \frac{i}{1}= 0+i

Therefore, the multiplicative inverse is   0+i1

Posted by

Gautam harsolia

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