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  • Find the probability distribution of the number of successes in two tosses of a die, where a success is defined as (ii) six appears on at least one die.

Q . 5: Find the probability distribution of the number of successes in two tosses of a die, where a success is defined as

             (ii) six appears on at least one die.

Answers (1)

best_answer

When a die is tossed twice, the total outcomes = 36

Six does not appear on any of the die  :  P(X=0)=\frac{5}{6} \times \frac{5}{6}=\frac{25}{36}

Six appear on at least one die: P(X=1)=\frac{1}{6} \times \frac{5}{6}+ \frac{1}{6}\times \frac{5}{6}=\frac{5}{18}

Probability distribution is as follows:        

X 0 1
P(X) \frac{25}{36} \frac{5}{18}

 

Posted by

seema garhwal

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